How can units of heat ever be ft^3/s?

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Homework Help Overview

The discussion revolves around the interpretation of units in a problem related to heat transfer and volumetric throughput rates. Participants are examining the use of the symbol Q in the context of heat transfer and its potential confusion with volumetric flow rates.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the use of the same symbol for different physical quantities, specifically whether Q refers to heat transfer or volumetric throughput. There is an exploration of whether the problem's author is equating these two concepts.

Discussion Status

There is an ongoing exploration of the definitions and assumptions surrounding the use of Q in the problem. Some participants are seeking clarification on the exact wording of the problem to better understand the context of the discussion.

Contextual Notes

Participants are noting potential confusion arising from the use of the same symbol for different concepts in physics, which may lead to misunderstandings in interpreting the problem.

craveneye13
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Homework Statement
I have a fluid mechanics textbook by Frank White which includes an example problem about a steady flow machine with one inlet and two outlets. The details of the actual problem are actually not so important as the follow: given information includes the areas of the inlets, the heat, the temperature, the pressure, and a height z. Included next to each given quantity is the unit in which its given. Next to heat, the unit is shown as (ft^3/s) where ft is feet and s is seconds. This is confusing me a bit. How can energy have those units? He subsequently even finds the fluid velocity at the inlets by dividing the heat by the inlet area, showing the units were not mistakenly typed. I am rather frustrated. Would anybody be able to explain how energy units would be length cubed over time?
Relevant Equations
Q (ft^3/s), A (ft^2), V (ft/s) => V = Q/A??? Where do the heat units come from??
Please and thank you!
 
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Q is the volumetric throughput rate, not heat.
 
Chestermiller said:
Q is the volumetric throughput rate, not heat.
Hello, thank you for your response. He does however explicitly refer to dQ/dt as the heat transfer rate in the very same problem. (it is in fact dQ/dt that we are set to find in the problem). Could it be that he is simply equating the volumetric through rate with the heat?
 
Chestermiller said:
Q is the volumetric throughput rate, not heat.
Does the use of that same letter for heat flow come from the theory of caloric fluid or did we just run out of alphabet to use?
 
craveneye13 said:
Hello, thank you for your response. He does however explicitly refer to dQ/dt as the heat transfer rate in the very same problem. (it is in fact dQ/dt that we are set to find in the problem). Could it be that he is simply equating the volumetric through rate with the heat?
Or I wonder if it is just an unfortunate use of the same letter ha
 
hutchphd said:
Does the use of that same letter for heat flow come from the theory of caloric fluid or did we just run out of alphabet to use?
I am beginning to suspect the latter, and I just conflated the two. Thank you for your help!
 
craveneye13 said:
Hello, thank you for your response. He does however explicitly refer to dQ/dt as the heat transfer rate in the very same problem. (it is in fact dQ/dt that we are set to find in the problem). Could it be that he is simply equating the volumetric through rate with the heat?
What is the exact word-for-word statement of the problem?
 

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