How Can We Calculate the Pressure Inside a Sphere With Varying Density Gas?

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SUMMARY

The discussion focuses on calculating the pressure inside a sphere filled with an ideal gas of varying density, defined by the formula ρ=ρo*(1-r/R), where R is the sphere's radius (5*1010 m) and r is the variable radius. The mass of the gas is given as M=3.3*1050 kg with a molar mass of 2.7 g/mol. The participant derives the force of gravity acting on an infinitesimal layer and formulates the differential pressure equation dp=dF/A, leading to the integral expression for pressure p(r). The method presented is valid and correctly applies principles of physics to solve the problem.

PREREQUISITES
  • Understanding of ideal gas laws, specifically pV=nRT.
  • Knowledge of calculus, particularly integration techniques.
  • Familiarity with gravitational force equations, including dF=GmM/r2.
  • Concept of varying density in a spherical coordinate system.
NEXT STEPS
  • Study the derivation of pressure in non-uniform gravitational fields.
  • Learn about the application of calculus in physics, focusing on integration of variable density functions.
  • Explore the implications of the ideal gas law in different physical scenarios.
  • Investigate advanced topics in fluid mechanics related to pressure distribution in spherical geometries.
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Students in physics or engineering disciplines, particularly those studying thermodynamics and fluid mechanics, as well as anyone involved in solving complex pressure-related problems in spherical systems.

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Homework Statement



I have a sphere filled with unknown gas. I have to estimate the pressure inside of it.

  • The tricky part is that density of the sphere changes as we go deeper inside of it with the given formula:
    ρ=ρo*(1-r/R), where R is radius of the sphere and is known: R=5*1010m, and r is a variable.
  • Gas has mol mass m=2.7 g/mol.
  • Mass of the whole sphere is M=3.3*1050 kg.
  • Gas is ideal.

Homework Equations



  • pV=nRT
  • p=F/A


The Attempt at a Solution



The force of gravity of an infinitesimal layer of thickness dr inside the sphere at some radius r caused by the inner sphere is:

dF=GmM/r2 where m is the mass of the infinitesimal layer and M is the mass of inner part of the sphere.

Mass m=V*ρ=4*PI*r2o*(1-r/R)*dr
Mass M=4/3*PI*r3o*(1-r/R)

so dF=G*16/3*PI2*r3o2*(1-r/R)2*dr

dp=dF/A
dp=dF/4*PI*r2
dp=4/3*PI*G*ρo2*(1-r/R)2*r*dr

so
p(r)=4/3*PI*G*ρo2*[tex]\int[/tex](1-r/R)2*r*dr from r to R

After making the calculations I will put p(r=0) and get the pressure inside the sphere. Is my method good?
 
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too hard or did I do something wrong?
 

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