How Can You Calculate Train Displacement in the First 3.15 Seconds of Motion?

[david12]

I try my best to solve this problem but couldn't ...here is the question

1.the train starting rest leaves a station with a constant acceleration.at the end of 5.34 s,it is moving at 15.549m/s. what is the train displacement in the first 3.15 s of motion?answer in units of meter.

I try in this way but couldn't get the answer.
I use velocity = displacement/time

15.549m/s= S/(5.34-3.15)

then i got 34.0523 m
after i got 34.05m i calculated the distance from 0s to 5.35 s which is 83.0316

finaly i subtract 83.0316 - 34.0523 = 48.97 m

but my answer is wrong so is there anyone can show me how i can do this question
thank you.

 

[Kurdt]

Are you familiar with the kinematic equations?

https://www.physicsforums.com/showpost.php?p=905663&postcount=2

With the given information you need to first find the acceleration of the train and then the displacement after 3.15s.