How can you differentiate xe^x csc x without using the product rule?

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SUMMARY

The differentiation of the function xex csc x can be effectively approached by extending the product rule to three variables. The correct derivative is obtained by applying the formula (fgh)' = f'gh + fg'h + fgh', where f = x, g = ex, and h = csc x. The initial attempt mistakenly suggested that the product rule was not applicable due to the presence of three terms, which is incorrect. Understanding the extension of the product rule is crucial for differentiating functions with multiple components.

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  • Understanding of basic differentiation rules
  • Familiarity with the product rule for derivatives
  • Knowledge of trigonometric functions, specifically csc and cot
  • Experience with exponential functions, particularly ex
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  • Practice differentiating functions involving trigonometric and exponential components
  • Learn about the chain rule and its applications in complex differentiation
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Students in calculus, mathematics educators, and anyone looking to enhance their skills in differentiating complex functions involving multiple variables.

r_swayze
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I don't really know how to even start this problem because I don't think the product rule would work here since there are three variables, right?

Here is my attempt at it:

xe^x csc x

xe^x csc x + xe^x (-csc x cot x)

xe^x (csc x - csc x cot x)

Used the product rule and that's what I came up with, can anyone give me a hint at what the first step is at least?
 
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You can easily extend the product rule to three terms. (fgh)'=f'gh+fg'h+fgh'.
 
thanks, that makes a lot more sense :)
 

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