How can you sell apples equally among three sons with the same procedure?

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BaRoN NiGhT
hi! I've got a puzzle.can u solve it?here it is:

a father has 90 apples.he has 3 children: A,B,and C.one day, the father told his children this:

Come here A, sell this 50 apples with the same procedure like your 2 brothers that result the same income
Come here B, sell this 30 apples with the same procedure like your 2 brothers that result the same income
Come here C, sell this 10 apples with the same procedure like your 2 brothers that result the same income

how can u sell it to have the same income between those three with the same procedure?

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[PLAIN]http://www.pesantren.net/khazanah/imej-pionir/ibnsina.jpg
Ibnu Sina (Avicenna in the West)
The Teacher of Kings
 
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as i understand i think each son could sell the apples for free so they will get the same income
or:
a=1/5 $ "for each apple"
b=1/3 $
c=1 $

am i right?
because i feel i am in a bigggggg wrong
 
not quite right.giving for free is not selling.as i said, they have to sell it.and the 1/5,1/3,and the 1 $ thing is also not the answer.its not the same procedure. ifyou sell it like that, the procedure would not be the same.the procedure has to be the same.

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http://www.pesantren.net/khazanah/imej-pionir/ibnsina.jpg
Ibnu Sina (Avicenna in the West)
The Teacher of Kings
 
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well, how about exagerating and selling each apple for [oo] $ (or whatever currency they used)?
 
ow c'mon, what apple costs [oo] $ ? this a real thing and can be done in a real life too.and this doesn't has a connection wtih currencies.

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[PLAIN]http://www.pesantren.net/khazanah/imej-pionir/ibnsina.jpg
Ibnu Sina (Avicenna in the West)
The Teacher of Kings
 
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What do you mean by procedure ?
 
origionally posted by jb

sell them by the pound

I agree.
 
Each sell a bag of apples for $10.
Each bag has all the apples given to each son.
 
Originally posted by Dave
Each sell a bag of apples for $10.
Each bag has all the apples given to each son.

guess my puzzle has some holes in it.i think it could be answered by daves answer, but that's not what i mean.well, i think i need to expose it, cause the inperfection of my puzzle that has been found by dave.my version is:


-put those apples in a bag with each bag contains 7 apples.sell it for 1 $
-the rest of apples,sell it with 7 $


now u can calculate that

A= (1$ x 7 bags) + 3$ x 1 apple = 10$
B= (1$ x 4 bags) + 3$ x 2 apples = 10$
C= (1$ x 1 bag) + 3$ x 3 apples = 10$

thats it.good for u dave!
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http://www.pesantren.net/khazanah/imej-pionir/ibnsina.jpg
Ibnu Sina (Avicenna in the West)
The Teacher of Kings
 
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