gracy
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Is my 48th post,correct?
But according to the video I have seen on concentration cell ,electrons are transferred not the ions.This is the video i am talking aboutBystander said:Salt bridges are used in laboratory applications, that is for cells that do no electrical work, nor have any electrical work done on them. One might be interested in comparing the concentrations of two different solutions of ferrous sulfate, for example, and it is necessary to prevent the solutions from mixing over the time frame of the measurement. Mixing is prevented by use of the salt bridge which allows for ionic current from a solution in one half cell (Fe/Fe+2) at one concentration to the second half cell (Fe/Fe+2) at a different concentration without the two solutions mixing or diffusing into one another and reducing the potential difference between the two half cells to zero before the measurement can be accomplished. Check the index in the textbook for "concentration cells."
What is mixing of solutions then?I thought that if ions of one half cell travel to second half cell ,it is said that solutions are mixed.Bystander said:Mixing is prevented by use of the salt bridge which allows for ionic current from a solution in one half cell (Fe/Fe+2) at one concentration to the second half cell (Fe/Fe+2) at a different concentration without the two solutions mixing or diffusing into one another
This is in the external circuit. The part of the circuit where chemistry is happening carries current in one, or both, directions by ion transport.gracy said:,electrons are transferred not the ions.
Yes.gracy said:Both of the processes will occur simultaneously ,the one i have mentioned in first option is to complete the circuit, and the second one to maintain neutrality ,right?
Any transfer of solute, ions, solvent, from one half cell to the other is "mixing." The idea behind the salt bridge is that the ion transfer is insignificant over the course of a measurement due to difficulty of diffusion through the salt bridge, or that the actual ion transport carrying the current involves the ions of the salt bridge, and that the salt be chosen to minimally interfere with the chemistry being measured/studied.gracy said:I thought that if ions of one half cell travel to second half cell ,it is said that solutions are mixed.
Only sufficient enough to complete the circuit?Bystander said:The idea behind the salt bridge is that the ion transfer is insignificant over the course of a measurement due to difficulty of diffusion through the salt bridge,
Yes.gracy said:sufficient enough to complete the circuit?
Ions of salt bridge also produce current?I thought they are only to maintain neutrality .Bystander said:that the actual ion transport carrying the current involves the ions of the salt bridge,
For every cation reduced at the cathode, to maintain neutrality, cation(s) must move through the salt bridge (carrying charge/current).gracy said:Ions of salt bridge alsoproducecarry current?
But at the same time For every anion oxidized at the anode, to maintain neutrality, anions must move through the salt bridge (carrying charge/current)Won't it cancel the current produced by cations of salt bridge?Bystander said:For every cation reduced at the cathode, to maintain neutrality, cation(s) must move through the salt bridge (carrying charge/current).
The two contributions are NOT necessarily equal. If you look at current through a Cu/Cu+2//Cu+2/Cu cell for refining/producing electrolytic copper, almost all the current carried through the cell is by Cu+2 ions. There is very little transport by SO4-2 ions which more or less maintain the electrical neutrality by playing "hot potato" or passing Cu+2 ions from one to another.gracy said:Won't it cancel the current produced by cations of salt bridge?
Drakkith said:I'm sorry but this is just wrong.
They don't. Electrons have a negative charge, protons have a positive charge, and neutrons are electrically neutral. You're replying to a bad answer.
The electrons that flow into the cathode are used in the chemical reaction between the cathode and the electrolyte. They are indeed 'lost' from the cathode in this reaction.
proton007007 said:The cathode is not charged