How Close Must Two Stationary Electrons Be to Double Their Mass?

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SUMMARY

To determine how close two stationary electrons must be to double their mass, one must consider the principles of relativistic mass and electrical potential energy. The total mass of the electrons can be expressed as m = 2(rest mass) when they are sufficiently close. The relevant equations include E = mc² and m = (rest mass) / (√(1 - (v²/c²))). The challenge lies in calculating the distance between the electrons, which requires equating the electrical potential energy to 2me².

PREREQUISITES
  • Understanding of relativistic mass and energy equations
  • Familiarity with the concept of electrical potential energy
  • Knowledge of special relativity, particularly velocity addition formulas
  • Basic grasp of the behavior of electrons in electromagnetic fields
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  • Research the derivation of electrical potential energy between charged particles
  • Study the implications of relativistic mass in particle physics
  • Explore the velocity addition formula in special relativity
  • Investigate the concept of rest mass versus relativistic mass
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Physicists, students studying advanced mechanics, and anyone interested in the implications of special relativity on particle interactions.

whitehorsey
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1. How close would two stationary electrons have to be positioned so that their total mass is twice what it is when the electrons are very far apart?


2. p = (mv) / (squareroot(1-(v2/c2))
E = (mc2) / (squareroot(1-(v2/c2))
E = mc2
m = (rest mass) / (squareroot(1-(v2/c2))
L = (proper length)*(squareroot(1-(v2/c2))


3. m = 2(rest mass)
m = (rest mass) / (squareroot(1-(v2/c2))
v = 6.75 * 1016


I solved up to the velocity but I don't know how to calculate the distance.



1. A spacecraft approaching the Earth launches an exploration vehicle. After the launch, an observer on Earth sees the spacecraft approaching at a speed of 0.50c and the exploration vehicle approaching at a speed of 0.70c. What is the speed of the exploration vehicle relative to the spaceship?

2. u = (u' + v) / (1 + (u;v/ c2))
u' = (u - v) / ( 1- (uv/c2))


3. I attempted this problem by setting u' equal to each other (each u either represents the exploration vehicle or the spaceship). But, I got stuck. I didn't know which v was for which vehicle/spaceship.
 
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whitehorsey said:
1. How close would two stationary electrons have to be positioned so that their total mass is twice what it is when the electrons are very far apart?


2. p = (mv) / (squareroot(1-(v2/c2))
E = (mc2) / (squareroot(1-(v2/c2))
E = mc2
m = (rest mass) / (squareroot(1-(v2/c2))
L = (proper length)*(squareroot(1-(v2/c2))


3. m = 2(rest mass)
m = (rest mass) / (squareroot(1-(v2/c2))
v = 6.75 * 1016


I solved up to the velocity but I don't know how to calculate the distance.
The electrical potential energy has to equal 2me2. What is the expression for that potential energy in terms of distance between the electrons?


1. A spacecraft approaching the Earth launches an exploration vehicle. After the launch, an observer on Earth sees the spacecraft approaching at a speed of 0.50c and the exploration vehicle approaching at a speed of 0.70c. What is the speed of the exploration vehicle relative to the spaceship?
Use http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/einvel.html#c1"

AM
 
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