1. The problem statement, all variables and given/known data Two spaceships, each 100m long when measured at rest, travel toward each other, each with a speed of .85c relative to the earth. At time t=0 on earth, the front ends of the ships are next to each other as they just begin to pass each other. At what time on earth are their backs next to eachother? 2. Relevant equations L = 1/γ * Lp t = L/u 3. The attempt at a solution So the length of each ship from earths frame is 1/γ * Lp which comes out to 53 meters, and then apparently the time it takes for their back ends to be together is the time it takes either spaceship to move the length of the spaceship in earth's frame. So it would be t = L/u which comes out to 2.1e-7 seconds. The book says this is the correct answer, but I don't understand. Why do you only need to calculate the time it takes for one spaceship to travel the length of a spaceship from earth's frame? Shouldn't the fact that they are both moving towards each other from earth's frame mean something? wtfz Special relativity is confusing me in general actually... can somebody explain the relativistic velocity transformation equations to me?? ux = (u'x + v) / (1+ (vu'x/c^2)) and yet.... uy = u'y / γ(1+ (vu'x/c^2)) how come the relative velocity of the particle in the x direction effects it's velocity transformation in the y direction? I know it has to do with the fact that the frame S and S' are moving apart from each other in the x direction but I can't quite connect the dots for making sense of this equation, anyone think they can enlighten me?