SUMMARY
The rate of heat absorption by a refrigerator can be calculated using the formula Rate of Heat Absorbed = Q/t, where Q is the heat removed and t is the time. In this case, the heat removed (Q) is calculated using Q = mcΔT, where m is the mass of water (2.15 kg), c is the specific heat capacity (4.2 J/kg°C), and ΔT is the temperature change (21.5°C to 0°C). The initial calculation yielded a rate of 2.6 x 10^-2 Js-1, but the correct answer for the total heat absorption rate, including the phase change from water to ice, is 1.27 x 10^2 Js-1.
PREREQUISITES
- Understanding of thermodynamics principles, specifically heat transfer.
- Familiarity with the specific heat capacity concept.
- Knowledge of phase changes in matter, particularly the freezing process.
- Ability to perform calculations involving mass, temperature change, and time.
NEXT STEPS
- Study the concept of latent heat and its role in phase changes.
- Learn about the specific heat capacity of different substances.
- Explore the first law of thermodynamics and its applications in refrigeration.
- Investigate the efficiency of refrigeration cycles and heat pumps.
USEFUL FOR
Students studying thermodynamics, physics educators, and professionals in refrigeration and HVAC systems.