How could I find the rate of heat absorption?

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Homework Statement



At what rate is a refrigerator absorbing heat if 2·15 kg of water at 21·5 °C is just frozen in 2·00 h?



Homework Equations



Q = mL
Q = mcΔT



The Attempt at a Solution



Rate of Heat Absorbed = Q/t
= mcΔT/t
= (2.15*4.2*21.5)/(2*60*60)
= 2.6*10^-2

The actual answer should be 1·27x10^2 Js-1
 
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You calculated the rate to lower the temperature of the water from 21.5 C to 0 C. After you remove this heat, the water will still be liquid. How much more heat do you have to remove to turn it into ice?