How Do a Dog and Man Walking at Different Speeds Meet Along a 1km Path?

  • Thread starter Thread starter lab-rat
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on a problem involving a dog and a man walking along a 1km path, where the dog walks at twice the speed of the man. The first meeting point occurs at 2/3 km from point A, as derived from the equation d = (2/3)Vman x t. Subsequent meeting points follow a predictable pattern based on their speeds and the total distance. The participants explore the mathematical reasoning behind their meetings and inquire about representing the problem graphically.

PREREQUISITES
  • Understanding of relative speed concepts
  • Basic algebra for solving equations
  • Knowledge of distance-time relationships
  • Familiarity with graphing linear equations
NEXT STEPS
  • Study relative speed problems in physics
  • Learn how to derive meeting points in motion problems
  • Explore graphical representation of linear equations
  • Investigate patterns in repetitive motion scenarios
USEFUL FOR

Students in mathematics or physics, educators teaching motion concepts, and anyone interested in solving relative speed problems.

lab-rat
Messages
44
Reaction score
0
The distance between point A and B is 1km. A dog and man start walking at the same time from point A toward point B. They will keep walking (if reached B then walk back toward A immediately, and if reached A then walk back toward B immediately, so on).

1.Given that the dog walks twice as fast as the man does.
(a) Where do they meet the first time? Show your reasoning.
(b) Where do they meet the second time? The third time? Show your reasoning.
(c) Any pattern observed?
(d) Where do they meet the 134th time?

I think I have (a) done, not sure though.
total distance = Vman x t + Vdog x t = 2
= Vman x t = 2Vman x t = 2
=3Vmant x t = 2
d=2/3 km

Not sure what to do next?? Thanks in advance!
 
Physics news on Phys.org
How do you suppose you could represnet this problem using straight line graphs?
 
genericusrnme said:
How do you suppose you could represnet this problem using straight line graphs?

Nice hint.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 20 ·
Replies
20
Views
2K
Replies
23
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
17
Views
1K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
34
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
Replies
4
Views
2K