- #1

mathmari

Gold Member

MHB

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A woman is walking home with distance $d$ and speed $v$.

The dog is happy and runs at speed $\frac{3v }{ 2}$ always between woman and house back and forth.

(i) At what distances $(d_n)_{n\geq 1}$ do women and dogs meet?

(ii) Determine the total path length of the dog with the help of $(d_n)_{n\geq 1}$.The time that woman needs is equal to $t=\frac{s}{v}$.

At the same time the distance that the dog makes is $s(d)=\frac{3v}{2}\cdot \frac{s}{v}=\frac{3s}{2}$, right?

But how can we get a formula for $(d_n)_{n\geq 1}$ ?

:unsure: