How Do Gas Particles Transfer Pressure in Elastic Collisions?

AI Thread Summary
Gas particles transfer pressure to the walls of a container through elastic collisions, where they retain their energy post-collision. This transfer of pressure occurs despite no energy loss, as pressure is a measure of force exerted over an area. The concept of pressure does not require work to be done, as pressure can exist without a volume change. The relationship between gas particle collisions and pressure is fundamental to understanding gas behavior in confined spaces. Thus, pressure can be exerted by gas particles even in the absence of work.
Forestman
Messages
212
Reaction score
2
I have read that when a gas atom or molecule collides with the wall of a container that the collision is completely elastic, and that the gas particle has the same energy after the collision as it did before the collision. I don't understand how it could transfer pressure to the container wall if it did not lose energy though.
 
Physics news on Phys.org
Pressure being transferred doesn't mean work is being done.

For work to be done there should be a pressure along with a volume change.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top