How do gradient and velocity relate on an inclined plane?

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SUMMARY

The discussion centers on the relationship between gradient and velocity on an inclined plane defined by the equation 4x + 5y + 6z = 45. Participants confirm that the gradient vector, represented by ∇F(x,y,z), indicates the direction of steepest descent or ascent. The velocity vector of a particle moving from the top to the bottom of the plane aligns with the gradient vector, establishing a direct proportionality between velocity and gradient. This relationship is crucial for understanding motion on inclined surfaces.

PREREQUISITES
  • Understanding of vector calculus, specifically gradient vectors.
  • Familiarity with the equation of a plane in three-dimensional space.
  • Basic knowledge of motion dynamics on inclined planes.
  • Concept of proportionality in physics and mathematics.
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  • Study the properties of gradient vectors in multivariable calculus.
  • Learn about the physics of motion on inclined planes, including forces and acceleration.
  • Explore vector fields and their applications in physics.
  • Investigate the relationship between potential energy and gradient in conservative fields.
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Students of physics and mathematics, particularly those studying vector calculus and dynamics, as well as educators seeking to explain the concepts of gradient and motion on inclined planes.

seamonkeydoo
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Gradient and velocity

Just curious

Let's say I have a plane with the equation

4x + 5y + 6z = 45

If I find [tex]\nabla[/tex]F(x,y,z) and then find it's magnitude, I get the direction of steepest descent/ascent in the direction of <[tex]\partial[/tex]F(x,y,z)/[tex]\partial[/tex]x,[tex]\partial[/tex]F(x,y,z)/[tex]\partial[/tex]y, [tex]\partial[/tex]F(x,y,z)/[tex]\partial[/tex]z> and the magnitude of the vector in that direction right?

How would I find the velocity vector of a particle from the top of the plane to the bottom in the direction of the gradient vector? Would I just think of it as an inclined plane? And how is velocity related to finding the gradient?
 
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Hi seamonkeydoo! Welcome to PF! :smile:
seamonkeydoo said:
How would I find the velocity vector of a particle from the top of the plane to the bottom in the direction of the gradient vector? Would I just think of it as an inclined plane?

uhh? It is an inclined plane! :confused:

Yes, the gradient vector "downhill" is the same as an actual vector "downhill".

Generally, the gradient vector of a curved surface is the same as the actual "downhill" vector of the tangent plane. :wink:
And how is velocity related to finding the gradient?

It'll be proportional to the gradient.
 

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