How do gradient and velocity relate on an inclined plane?

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seamonkeydoo
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Gradient and velocity

Just curious

Let's say I have a plane with the equation

4x + 5y + 6z = 45

If I find [tex]\nabla[/tex]F(x,y,z) and then find it's magnitude, I get the direction of steepest descent/ascent in the direction of <[tex]\partial[/tex]F(x,y,z)/[tex]\partial[/tex]x,[tex]\partial[/tex]F(x,y,z)/[tex]\partial[/tex]y, [tex]\partial[/tex]F(x,y,z)/[tex]\partial[/tex]z> and the magnitude of the vector in that direction right?

How would I find the velocity vector of a particle from the top of the plane to the bottom in the direction of the gradient vector? Would I just think of it as an inclined plane? And how is velocity related to finding the gradient?
 
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Welcome to PF!

Hi seamonkeydoo! Welcome to PF! :smile:
seamonkeydoo said:
How would I find the velocity vector of a particle from the top of the plane to the bottom in the direction of the gradient vector? Would I just think of it as an inclined plane?

uhh? It is an inclined plane! :confused:

Yes, the gradient vector "downhill" is the same as an actual vector "downhill".

Generally, the gradient vector of a curved surface is the same as the actual "downhill" vector of the tangent plane. :wink:
And how is velocity related to finding the gradient?

It'll be proportional to the gradient.