How do I calculate specific heat capacity in a lab report?

[soccerLuver]

Homework Statement

Homework Equations

i have a problem solving this foe my lab report..i just don't get the formula
heres the data:
ethylene glycol...its mass is 200 g ,initial temperature 22C, temperature after heated 100C
what is its heat capcity?

metal and water
mass of metal-15.8 g
temperature of water-23 C
temperature of metal and washers-24 C
what is the heat gained by the water assuming the heat gained by the water is equal to the heat lost by the metal?
what is the heat capacity of the metal?

any clue..or formula?

The Attempt at a Solution

200( 1cal/gC) (1) / 15.8 (1)

 

[Borek]

In general, formula that you are looking for is most likely

q=c*m*ΔT

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methods