How do I calculate the outward force exerted by a wedge on a rotating plate?

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SUMMARY

The discussion focuses on calculating the outward force exerted by a wedge on a rotating plate with a diameter of 8 feet and a wedge height of 2 feet. The wedge's base measures 20 feet across, and the torque applied to the system is 52,920 ft/lbs. Participants emphasize the need for clarity regarding the wedge's orientation and the relationship between the wedge dimensions and the plate's circumference. A visual representation of the setup is suggested to facilitate understanding.

PREREQUISITES
  • Understanding of basic physics concepts, particularly torque and force.
  • Familiarity with geometry, specifically calculating areas and dimensions of wedges.
  • Knowledge of rotational dynamics and how forces interact in rotating systems.
  • Ability to interpret diagrams and visual representations of mechanical systems.
NEXT STEPS
  • Research the calculation of forces in rotating systems, focusing on wedges and cams.
  • Learn about torque calculations and their application in mechanical engineering.
  • Explore the principles of radial and tangential forces in rotating bodies.
  • Study the use of diagrams in mechanical problem-solving to enhance clarity and understanding.
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in designing or analyzing rotating systems with wedges or cams will benefit from this discussion.

mcashatt
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This is not a homework question! I am not a physics guru (clearly) and need help solving what I think is probably a simple calculation for someone who knows what they're doing:

I have a rotating plate with a "ramp" or wedge growing out of the perimeter of the plate. The wedge is perpendicular to the plate. The diameter of the plate is 8' so the circumference is 25.12'. For the sake of this calculation, assume that the bottom of the wedge is 20' across and the height of the wedge at the end is 2'. What I need to know is how to calculate the outward force exerted by the wedge (this would be the force perpendicular to the plate). I know the torque that I will apply (the force parallel to the plate): 52,920 ft/lbs.


Any help would make a sane man out of me.

Thanks!

Matt
 
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a drawing or picture would help...
 
You say that the bottom of the wedge is 20 inches across, and yet you prevoiusly said that the disk was 25+ inches in diam. How do these two relate?

Is this a face cam? You talk about wanting the outward force exerted by this wedge. Is that radially outward, or is that paralled to the axis of rotation?

As dipstik said, we really need a picture.
 

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