How Do I Calculate Thermal Efficiency with the Brake Equation?

  • Thread starter Thread starter recreated
  • Start date Start date
  • Tags Tags
    Efficiency Thermal
Click For Summary

Discussion Overview

The discussion centers around calculating thermal efficiency using the brake equation, specifically addressing the confusion surrounding the units of brake specific fuel consumption (bSPC) and heating value (QHV). The scope includes mathematical reasoning and unit conversion in the context of engineering applications.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant seeks assistance in calculating thermal efficiency using the formula: Thermal Efficiency, Brake = 1/(bSPC x QHV), expressing uncertainty about the correct SI units for bSPC and QHV.
  • Another participant confirms the equation is correct and suggests reducing all terms to a consistent set of units, explaining the conversion of kWh to MJ.
  • A participant expresses relief at solving the problem after receiving help, indicating a sense of frustration prior to understanding the unit conversions.
  • Another participant reiterates that the units are the source of confusion, emphasizing the need to convert bSPC to align with the heating value before using it in the efficiency formula.
  • A later reply suggests that writing out units can help identify missing factors, highlighting the importance of unit cancellation in efficiency calculations.
  • One participant expresses gratitude and a desire to learn more about manipulating units for future applications in Mechanical Engineering.

Areas of Agreement / Disagreement

Participants generally agree that the confusion arises from the units used in the calculation, and multiple suggestions for resolving the issue are presented. However, there is no explicit consensus on a single method or approach to the problem.

Contextual Notes

Limitations include potential misunderstandings regarding unit conversions and the specific definitions of bSPC and QHV, which may affect the calculations. The discussion does not resolve these limitations.

Who May Find This Useful

This discussion may be useful for students or professionals in engineering fields, particularly those dealing with thermal efficiency calculations and unit conversions.

recreated
Messages
45
Reaction score
1
Can you please help me? I am trying to calculate this equation but can't get correct answer:

Thermal Efficiency, Brake = 1/(bSPC x QHV)

bSPC (brake Specific fuel consumption) = 0.396 kg/KWh

QHV (Heating Value for fuel) = 44 MJ/Kg

The correct answer is meant to be: Thermal Efficiency, Brake = 0.207 = 20.7%.

I do not know the correct SI units for bSPC or QHV, hopefully I am not using the right ones because I can't get that answer.

Look forward to any help or advise, Thanks
 
Last edited:
Physics news on Phys.org
Your equation is correct, but I think what is confusing you are the prefixed units. What you can do is reduce everything to the same set of units.

kWh is a unit of energy so 1kWh = 1 kW * 1 hr = 1kJ/s * 3600 s = 3600 kJ = 3.6 MJ

So your bSPC = .396 kg/kWh = 0.396/3.6 kg/MJ
 
  • Like
Likes   Reactions: 1 person
Wow solved perfectly, and can get correct answer,, must have been <30mins. You don't know how stupid I felt not being able to do that equation. Thank you very much
 
Your units are at fault. The bSPC is given in units of kg/kWh while the HV is given in MJ/kg.

You need to find the heat equivalent of kWh and convert the value of bSPC before plugging it nto the efficiency formula.
 
recreated said:
Wow solved perfectly, and can get correct answer,, must have been <30mins. You don't know how stupid I felt not being able to do that equation. Thank you very much

Another thing that I found helpful to do is to write out your units so that you know if you are missing out a factor.

So for efficiency, it would be output power/input power which means that you units would cancel.

Just multiplying the numbers would have left you with something like MJ/kWh and you would have neglected a factor.
 
Thank you both soo much. I am going to learn today about manipulating units, it will help me soo much with Mechanical Engineering.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
6K
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 2 ·
Replies
2
Views
13K
Replies
9
Views
9K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K