How Do I Calculate Voltage Drop Without Knowing Current?

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Discussion Overview

The discussion revolves around calculating voltage drop in an electrical circuit without knowing the current. Participants explore the relationship between impedance and voltage drop, particularly in the context of a TN system with specific parameters.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant presents the formula Zs = Ze + Z1 + Z2 and provides specific values for Z1 and Z2, questioning how to incorporate voltage drop without knowing the current.
  • Another participant suggests that if the fuse is rated at 32A, the current could be any value less than 32A, implying uncertainty about the actual current in the circuit.
  • A participant outlines their attempt at a solution, calculating Zs and proposing a relationship between voltage, impedance, and current, but expresses uncertainty about the correctness of their approach.
  • There is mention of relevant standards regarding maximum voltage drop percentages for different types of circuits, but the participant is unsure if this information is applicable to their situation.
  • A request for assistance is made, indicating a lack of responses to the initial inquiry.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to calculate voltage drop without knowing the current, and multiple viewpoints regarding the approach and relevance of certain parameters remain unresolved.

Contextual Notes

Participants express uncertainty about the implications of their calculations and the relevance of voltage drop standards, indicating potential limitations in their understanding of the problem.

Who May Find This Useful

This discussion may be useful for individuals studying electrical engineering or those seeking to understand voltage drop calculations in practical applications.

scarecrow75
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Hi all

Wondering if anyone can help. Really don't know where to start

I know Zs = Ze + Z1 + Z2

and Z1 = PCR 8.9 milli-ohms/meter
and Z2 = CPC 14.5 milli-ohms/meter
which equates to 0.0234X milli-ohms/meter over X meters

but where does my volt drop come in if I don't know my current?

Regards
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scarecrow75 said:
but where does my volt drop come in if I don't know my current?

If the fuse is 32A the current could be any value <32A ??
 

Homework Statement


230 V, 50 Hz supply (TN)
Ze = 0.8 ohms
Z1 = 8.9 milli-ohms/meter
Z2 = 14.5 milli-ohms/meter
Volt-drop/Amp/meter = 18 mV/A/m

Homework Equations


Zs = Ze + Z1 + Z2
V / Zs = I ?

The Attempt at a Solution


Zs = Ze + Z1 + Z2
Zs = 0.8 + (0.0089 + 0.0145)X......where X is the distance in meters
Zs = 0.8 + 0.0234X

Then
230V / (0.8 + 0.0234X) = I

Not sure if this is correct!
Also is this relevant:
TN system... I know that for final circuits up to 32A disconnection time should not exceed 0.4secs
Voltage Drop, lighting circuits = 3%max and other circuits 5% max
if this is correct then 230V * 0.05 = 11.5V

Not sure if this is right approach

Any help?

Cheers
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