How do I expand the chain rule to second partial derivatives?

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The discussion focuses on expanding the chain rule to compute second partial derivatives for the function f(x(y,z), t(y,z)). The user initially expresses uncertainty about deriving the second derivative d²f/dz² after establishing the first derivative as df/dz = df/dx * dx/dz + df/dt * dt/dz. The solution provided utilizes subscript notation, leading to the expression fzz = (fxxz)x * xz + (fxxz)t * tz, confirming the necessity of applying the product rule within the calculation.

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rabbleguy
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We have f(x(y,z),t(y,z)).

This is more of a study question. I don't know how to expand out [tex]d^{2}f/dz^2[/tex]


I know df/dz = df/dx*dx/dz + df/dt*dt/dz, but I don't know how to expand this to the 2nd derivative. I think the product rule comes into play? Not really sure.

Thanks for your help.
 
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Using the more convenient subscript notation, you have used:

fz = fxxz+ fttz

Now you have to do the same thing to this expression, which can be done termwise:

fzz =(fxxz)x[itex]\cdot\,[/itex]xz + (fxxz)t[itex]\cdot\,[/itex]tz

and, yes, you will need the product rule inside those parentheses.
 

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