- #1

Jim4592

- 49

- 0

## Homework Statement

find dy/dx for x

^{2}y+xy

^{2}=6

## Homework Equations

## The Attempt at a Solution

d/dx (x

^{2}y+xy

_{2}) = d/dx (6)

x

^{2}*(dy/dx)+y*2x+x*2y(dy/dx)+2y=0

x

^{2}*(dy/dx)+y*2x+x*2y(dy/dx)=-2y

(dy/dx)+y*2x+x*2y(dy/dx)=(-2y/x

^{2})

(dy/dx)+y*2x+(dy/dx)=(-2y/x

^{2}+2xy)

I'm not sure what to do now, i know that the answer is (2xy-y

^{2}/x

^{2}+2xy)

I got the denominator correct in my answer but I'm not sure how to get the numerator correctly. Did I go wrong somewhere during the process?