How do I find the derivative of the square root of (2x+1) using the chain rule?

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SUMMARY

The derivative of the square root of (2x+1) can be effectively calculated using the chain rule. First, express the function as (2x+1)^(1/2). Apply the chain rule by taking the derivative of the outer function, which is (1/2)(2x+1)^(-1/2), and multiply it by the derivative of the inner function, which is 2. Thus, the final derivative is (1/2)(2x+1)^(-1/2) * 2, simplifying to 1/(sqrt(2x+1)).

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  • Familiarity with the chain rule in differentiation.
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tad.confused
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I need to find the derivative of the square root of (2x+1) (not sure how to do square root symbol here, sorry)

I understand that the square root of (2x+1)= (2x+1)^(1/2), but I am getting a little confused on how to continue from there.
 
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From (2x+1)^(1/2) you should use the chain rule. take the derivative of the inside and multiply it by the derivative of the outside, when taking derivative of outside use substitution.
 

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