How do I find the distance between two lines passing through different points?

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To find the distance between two lines defined by points A(2,1,2), B(3,2,-1) and C(-1,2,4), D(-2,1,3), it is essential to determine if the lines are parallel or skewed. The vectors AB and CD are calculated as AB = (1,1,-1) and CD = (-1,-1,-1), confirming that the lines are skewed. The distance between the skew lines can be found using vector projection and the cross product of the direction vectors, specifically through the equation involving the vector product N = AB × CD. It is also advised to visualize the problem with a diagram for better understanding. The approach requires careful application of vector equations and geometric principles.
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Homework Statement



Okay thanks everyone for taking the time to read this quesiton. Now I sort of know how to do this question but I am not entirely sure how I should approach it:

I have points A(2,1,2) B(3,2,-1) C(-1,2,4) and D(-2,1,3)

Now a line passes through points A and B and also C and D respectively. What essentially we need to find is that the line that passes through A and B is at least 1 metre apart from the line that passes through C and D

Homework Equations



Dot Product, cross product. unit vector, shortest distance between two points*

The Attempt at a Solution


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So in order for there to be a distance we must check if the lines are parallel or not...
After conducting a test I found that these lines are skewed.

What I am confused about is this. I have 4 sets of coordinates now I know if I do

AB = B - A = (1,1,-1)

and CD = D - C = (-1,-1,-1) I get two vector equations

Now to find the distance between two vector equations we use vector projection and the unit vector but I am not sure how I can lay that out
 
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So you have two lines ##\vec A + \lambda(\vec B - \vec A)## and ##\vec C + \mu (\vec D - \vec C)##.
If I follow this example I need the veector product ##\vec N = \vec {AB} \times \vec {CD}## as the main step.

And note their extremely important tip: make a picture to see what you are doing !
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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