How do I find the equation of motion for this object?

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To find the equation of motion for the object, the derivative of the total energy must be set to zero, leading to the expression involving mass, angular velocity, and gravitational force. The discussion highlights confusion regarding the concept of an equation of motion and its expected format. Clarification is sought on what constitutes an equation of motion, suggesting a review of introductory materials on the topic. Additionally, there is a request for the complete problem statement and a recommendation to use LaTeX for better presentation of equations. Understanding the foundational concepts is crucial for progressing in solving the problem.
1v1Dota2RightMeow
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Homework Statement


Find the equation of motion of the object by setting the derivative of the total energy equal to zero.

Homework Equations


r(theta)=(Rcos(theta), Rsin(theta), q*theta)

v(theta)=dr/dt=(-Rsin(theta)dtheta/dt, Rcos(theta)dtheta/dt, q*dtheta/dt)

derivative of Total Energy = m(dtheta/dt)(d^2theta/dt^2)(R^2+q^2)+m*g*q*dtheta/dt

The Attempt at a Solution


I worked it all out to the point of finding the derivative of the total energy above. But I'm confused now. What does it mean to find an equation of motion? Let's start with that because if I don't know what an equation of motion will even look like, then I won't have any clue if I've found it or if I'm even on the right track.
 
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1v1Dota2RightMeow said:
What does it mean to find an equation of motion?
See here https://en.wikipedia.org/wiki/Equations_of_motion about equations of motion.
Other than that, please provide the complete problem statement, not just the question of what you are required to find. Also, it would be nice to use LaTeX for your equations. The time you invest learning it is worth it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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