what is the total electric field at the meeting point of the 2 if we bring them close together so that they touch at point A?

what i did was:

the ball has spherical symetry and the pipe has cylindrical symetry, so those are the shapes i will use for my gauss law,

since R

_{A}=R

for the ball

[tex]\Phi[/tex]=EA=E(4[tex]\Pi[/tex]R

^{2})=[tex]\sigma[/tex](4[tex]\Pi[/tex]R

^{2})/[tex]\epsilon[/tex]

_{0}

E=[tex]\sigma[/tex]/[tex]\epsilon[/tex]

_{0}

for the pipe

[tex]\Phi[/tex]=EA=E(2[tex]\Pi[/tex]R*L)=[tex]\sigma[/tex]2[tex]\Pi[/tex]R*L)/[tex]\epsilon[/tex]

_{0}

E=[tex]\sigma[/tex]/[tex]\epsilon[/tex]

_{0}

does this mean that the total field at point A will be 0 since they have the same field in opposite directions?

does that make sense?