How do I find the position vector for the line of intersection?

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SUMMARY

The discussion focuses on finding the vector equation for the line of intersection between two planes defined by the equations 2x - y - 3z = 7 and x + 2y + 2z = 0. A direction vector of 4i - 7j + 5k was correctly identified using the vector product. To determine the position vector, it is essential to find a point that lies on both planes, which can be achieved by setting z = 0 and solving for the intersection in the x-y plane.

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Homework Statement



Two planes have equations
2x-y-3z=7
x+2y+2z=0

Find a vector equation for their line of intersection

The Attempt at a Solution



I haven't learned the vector product in class but read it and attempted it and got the direction vector 4i-7j+5k.
However, I don't know how to get the position vector of this.



Thank you for your help and time
 
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You have done most of the work. You did the vector product correctly, and have found the vector coordinates for a line parallel to the line of intersection. Now all you need is a point contained in both planes. The line of intersection will then be parallel to the direction vector you found and will run through that point. I recommend letting z = 0 and finding the point where the planes intersect in the x-y plane. If you have any problems, let us know.
 

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