MHB How do I Find the Vector Coordinates to Solve for Trihedral Angle?

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To find the vector coordinates for a unit vector C that forms angles α and β with given unit vectors A and B, the angles must satisfy the conditions α + β = φ and α + β + φ ≤ 360°. The user initially derived two equations from the dot products: A·C = cos(α) and B·C = cos(β). A third equation is necessary, which is provided as the triple product A·(B×C) = V. The solution involves using the derived equation V² = 1 + 2*cos(α)*cos(β)*cos(φ) – cos²(α) – cos²(β) – cos²(φ) to find the coordinates of vector C.
Julian1
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Hi everyone,

Here's the problem I have.

Given two unit vectors A, B and angle φ between them. Find the coordinates (in 3D) of a unit vector C so that the angles between C and A,B be α and β respectively.
α + β => φ and α + β + φ <= 360°

It looks trivial to me and yet here I am asking for help:)

I have two equations from the dot products:
A.C = cos(α)
B.C = cos(β)

and I need a third one to solve the problem?

Thanks!Julian.
 
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Re: find the vector coordinates

I have found the solution.

The third equation is the triple product.

A.BxC = V

where

V2 = 1 + 2*cos(α)*cos(β)*cos(φ) – cos2(α) – cos2(β) – cos2(φ)

Trihedral Angle | OPEN MIND
 
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