How Do I Simplify This Circuit for My Test Preparation?

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To simplify the circuit for test preparation, recognize that resistors R6, R7, and R8 are connected in parallel to E2, while R3, R4, and R5 are parallel to E1. This configuration allows for a simplified analysis of the circuit. By focusing on these parallel connections, the overall circuit can be drawn more clearly. Understanding these relationships will aid in circuit simplification and preparation for tests. Simplifying the circuit in this manner makes it easier to analyze and solve.
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I'm learning and preparing myself for test, but I'm stuck. I don't know how to simplified this

[PLAIN]http://img814.imageshack.us/img814/4977/42625320.png
 
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Noticed how each of R6,7,8 has one end connected to E2+ and the other connected to E2-? So Actually they're parallelly wired to E2.

You have the same for R3,4,5 and E1.

That actually leaves you with a pretty simple circuit, which I'll let you draw on your own.
 
thanks
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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