- #1
Pietair
- 59
- 0
Good day,
How do I work out (a+b)^(-c)?
Thanks.
How do I work out (a+b)^(-c)?
Thanks.
The formula for solving (a+b)^(-c) is 1/(a+b)^c.
To simplify (a+b)^(-c), you can rewrite it as 1/(a+b)^c and then use the rules of exponents to simplify further.
Yes, (a+b)^(-c) can be negative if both a and b are negative and c is an odd number. For example, if a=-2, b=-3, and c=3, then (a+b)^(-c) would be -1/125.
If c is a fraction, for example c=1/2, then (a+b)^(-c) can be rewritten as 1/sqrt(a+b) and simplified using the rules of exponents.
If a, b, and c are variables, then you can use algebraic manipulation and the rules of exponents to simplify (a+b)^(-c) as much as possible. If a more specific solution is needed, you can substitute in numerical values for the variables and solve using a calculator or computer program.