How do I solve an inverse Laplace problem with an unfactorable denominator?

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SUMMARY

The discussion focuses on solving the inverse Laplace transform of the function (2s+2)/(s^2+2s+5). The key challenge is the unfactorable denominator, which can be addressed by completing the square, transforming it into the form (s+1)² + 4. Participants emphasize the importance of recognizing entries in Laplace tables that involve the structure s² + a², and suggest rewriting the numerator as 2(s+1) + b to facilitate the transformation.

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georgeh
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i have the following problem
(2s+2)/(s^2+2s+5)
I am suppose to find the inverse laplace by putting in a form that i can find in a Laplace table, unfortunately the denominator does not factor!... not sure how to procede.
 
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Try completing the square. s2+ 2s+ 5= s2+ 2s+ 1+ 4= (s+1)2+ 4. Do you have a entry in your table that involves s2+ a2 in the denominator?
Can you write 2s+ 2 as 2(s+1)+ b?

Does your table of inverse Laplace transforms have a suggestion if you have (s+ a) instead of s?
 
yeah it does, thanks I got it.
 

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