How do I solve an inverse Laplace problem with an unfactorable denominator?

[georgeh]

i have the following problem
(2s+2)/(s^2+2s+5)
I am suppose to find the inverse laplace by putting in a form that i can find in a Laplace table, unfortunately the denominator does not factor!... not sure how to procede.

 

[HallsofIvy]

Try completing the square. s²+ 2s+ 5= s²+ 2s+ 1+ 4= (s+1)²+ 4. Do you have a entry in your table that involves s²+ a² in the denominator?
Can you write 2s+ 2 as 2(s+1)+ b?

Does your table of inverse Laplace transforms have a suggestion if you have (s+ a) instead of s?

 

[georgeh]

yeah it does, thanks I got it.