How Do I Solve This Combination Circuit?

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Homework Help Overview

The discussion revolves around a combination circuit involving various resistors, where participants are attempting to calculate the equivalent resistance. The original poster expresses confusion over their calculated value of 62K, which does not match the provided answer choices.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss different methods for calculating equivalent resistance, including treating resistors as series and parallel combinations. There are attempts to clarify the steps taken and to verify calculations, with some participants questioning the assumptions made about the circuit configuration.

Discussion Status

The discussion is ongoing, with participants providing guidance on calculation methods and clarifying steps. There appears to be some confusion regarding the correct approach to combining resistances, and multiple interpretations of the circuit setup are being explored.

Contextual Notes

Participants note discrepancies in their calculations and the expected answers, leading to discussions about the order of operations and the treatment of resistors in series versus parallel. There is an acknowledgment of potential errors in previous calculations.

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Could somebody help me out with this combination circuit? The answer that I get is 62K but that is not one of the answers. At first, I thought the 10kohm and 20kohm wherein series and the other side as well. Then I thought they are all in parallel because of the different current flow they all can take but I couldn't figure out the answer. Any help will be appreciated.

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So show how you did it.

I did the parallel resistors to get a single value.
Then added the series resistance.
Then the one in parallel.
Then added the two series resistances.

They've made the values all work out easily. There are no difficult sums. You could probably do it in your head, but better write it down for checking.
 
Merlin3189 said:
So show how you did it.

I did the parallel resistors to get a single value.
Then added the series resistance.
Then the one in parallel.
Then added the two series resistances.

They've made the values all work out easily. There are no difficult sums. You could probably do it in your head, but better write it down for checking.

So from what you are saying is getting the 24k,24k,40k,and 60k in parallel getting 8k then adding the 22k and 2k which would be 32k. Finding the parallel of the 32k with the 20k and getting 12k, adding the 10k which would be 22 and still not getting the right answer.
 
atoms said:
So from what you are saying is getting the 24k,24k,40k,and 60k in parallel getting 8k Yes
then adding the 22k and 2k which would be 30k. No. First, 8+22+2 = 32. But you can't add all three yet. So keep one for later.
Finding the parallel of the 30k with the 20k and getting 12k, Yes
adding the 10k which would be 22 Yes
and still not getting the right answer. Only 3 out of 4 yeses
resistors_reduction2.png

BTW. You haven't shown how you got 62k yet
 

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Last edited:
Merlin3189 said:
View attachment 232555
BTW. You haven't shown how you got 62k yet
So the outer resisitors I add at the end once I calculate the inside. Thank you
 
I added the 32 from the bottom and the 30 on top which was terribly wrong
 
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