How Do I Solve This Combination Circuit?

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SUMMARY

The discussion focuses on solving a combination circuit involving resistors of various values, specifically 10kΩ, 20kΩ, 22kΩ, 24kΩ, 2kΩ, 40kΩ, and 60kΩ. Participants detail their methods for calculating total resistance by first combining resistors in parallel and then adding series resistances. The correct approach involves calculating the parallel resistances to obtain a single value before adding series resistances, ultimately leading to the correct total resistance. Miscalculations and misunderstandings about the order of operations are highlighted, emphasizing the importance of systematic problem-solving in circuit analysis.

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  • Understanding of Ohm's Law
  • Knowledge of series and parallel resistor combinations
  • Familiarity with resistor values and their symbols
  • Basic circuit analysis skills
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Could somebody help me out with this combination circuit? The answer that I get is 62K but that is not one of the answers. At first, I thought the 10kohm and 20kohm wherein series and the other side as well. Then I thought they are all in parallel because of the different current flow they all can take but I couldn't figure out the answer. Any help will be appreciated.

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So show how you did it.

I did the parallel resistors to get a single value.
Then added the series resistance.
Then the one in parallel.
Then added the two series resistances.

They've made the values all work out easily. There are no difficult sums. You could probably do it in your head, but better write it down for checking.
 
Merlin3189 said:
So show how you did it.

I did the parallel resistors to get a single value.
Then added the series resistance.
Then the one in parallel.
Then added the two series resistances.

They've made the values all work out easily. There are no difficult sums. You could probably do it in your head, but better write it down for checking.

So from what you are saying is getting the 24k,24k,40k,and 60k in parallel getting 8k then adding the 22k and 2k which would be 32k. Finding the parallel of the 32k with the 20k and getting 12k, adding the 10k which would be 22 and still not getting the right answer.
 
atoms said:
So from what you are saying is getting the 24k,24k,40k,and 60k in parallel getting 8k Yes
then adding the 22k and 2k which would be 30k. No. First, 8+22+2 = 32. But you can't add all three yet. So keep one for later.
Finding the parallel of the 30k with the 20k and getting 12k, Yes
adding the 10k which would be 22 Yes
and still not getting the right answer. Only 3 out of 4 yeses
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BTW. You haven't shown how you got 62k yet
 

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Merlin3189 said:
View attachment 232555
BTW. You haven't shown how you got 62k yet
So the outer resisitors I add at the end once I calculate the inside. Thank you
 
I added the 32 from the bottom and the 30 on top which was terribly wrong
 
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