How Do Newton's Laws Explain Motion in Everyday Scenarios?

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SUMMARY

This discussion focuses on applying Newton's Laws of Motion to solve practical problems involving forces and motion. Key calculations include determining the net force on a skydiver, calculating the stopping distance of a car using friction, and finding the speed of a car moving in a circular path. The net force on the skydiver is 60 N, the stopping distance for the car is approximately 45.92 m, and the speed of the car making a complete revolution in 22 seconds is derived from the circumference divided by time. Participants confirm the correctness of the calculations for the first two problems.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Basic knowledge of force and acceleration calculations
  • Familiarity with friction coefficients and their application
  • Ability to calculate circular motion parameters
NEXT STEPS
  • Study the application of Newton's Second Law in various scenarios
  • Learn about the effects of friction on motion in different surfaces
  • Explore circular motion equations and their derivations
  • Investigate real-world applications of Newton's Laws in engineering
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Students studying physics, educators teaching motion concepts, and anyone interested in applying Newton's Laws to real-world scenarios.

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(1) What is the magnitude of the net force on a skydiver in N when an 810 N gravitational force and a 750N force of air resistance act on him?

Fn = 810
Fg = 750

810 - 750 = Fm

60N

(2) A 1200 kg car is moving in a staright line at a constant speed of 15m/s when the brakes are applied. The coefficeient of friction between the car and the road is 0.25. How far in m does the car travel after the brakes are applied?



Fn = 1200*9.8

F = u*Fn = 2940N

-F = m*a

a = -F/m = -2940/1200 = -2.45m/s^2

Vf^2 = Vi^2 +2a*deltaX

0 = Vi^2 +2adeltaX

-Vi^2/2a = deltaX = -15^2/-2.45 = 45.92m


4.) A car moves in a circle of 30 m radius. It moves with constant speed and makes one complete revolution in 22s. What is its speed in m/s?

A = V^2/r

that's all I have for this problem..

can you guys help me out with this?

Also, are my answers for 1 and 2 correct?
 
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1 & 2 are good.

Notice that you do not need to know the mass for the problem in 2. If friction is only force (and therefore the net force) on an object, and it is sliding on a horizontal surface, notice that the acceleration is always \mu g

for #3 you are making it too hard. speed is what over what?

In one full circle, the distance traveled is known as the __________ .
 
Last edited:
What about 3, sir. Any advice how to start it?
 
check previous post. I added it late.
 
nevermind..I think i got it..I think it's just circumference over time..so 60pi/22
 

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