How Do Power, Force, and Velocity Interact?

AI Thread Summary
The discussion focuses on the interaction of power, force, and velocity in the context of a lorry moving up a slope. Participants emphasize the importance of calculating the motive force required to overcome resistive forces, including gravitational components and friction. It is clarified that the power produced by the engine can be calculated using the formula P = F * v, where F represents the total force acting on the vehicle. The conversation also highlights that the net force is zero when the speed is constant, but the engine must provide enough force to counteract resistance. Overall, the key takeaway is that the effective power is determined by the force exerted by the engine and the velocity of the lorry.
hello478
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Homework Statement
question c part ii) power produced by engine
Relevant Equations
p= f* v
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8628.46 ?

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BvU said:
8628.46 ?

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its by finding the component of weight along slope
 
So the slope is given, and so is the mass of the lorry. Given for you , that is.
But my telepathic capabilities are limited and I need a complete problem statement, typed out.

And: what are the directions of 8628.46 and the resistive force ?

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BvU said:
So the slope is given, and so is the mass of the lorry. Given for you , that is.
But my telepathic capabilities are limited and I need a complete problem statement, typed out.

And: what are the directions of 8628.46 and the resistive force ?

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i have attached the question image above..., is it not there? let me check again
 
hello478 said:
Homework Statement: question c part ii) power produced by engine
Relevant Equations: p= f* v

View attachment 342385
View attachment 342389
The F you need to use in P=Fv is the motive force delivered by the engine. This has to balance the opposing forces, the 5200N of resistance plus the gravitational component.
 
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haruspex said:
The F you need to use in P=Fv is the motive force delivered by the engine. This has to balance the opposing forces, the 5200N of resistance plus the gravitational component.
ok so in p=fv
the f would always be total force?
 
hello478 said:
ok so in p=fv
the f would always be total force?
Depends what you mean by "total force". As you wrote, since the speed is constant the total force on the truck is zero.
 
haruspex said:
Depends what you mean by "total force". As you wrote, since the speed is constant the total force on the truck is zero.
yeah the net force would be zero
but here... we would have to use the force which is causing the body to move(the total force, sum of resistive forces) with that velocity???
is this explanation fine?
 
  • #10
hello478 said:
yeah the net force would be zero
but here... we would have to use the force which is causing the body to move
Yes, that being the static frictional force on the tyres. We can consider that the motive force provided by the engine, though in reality what the engine provides is a torque.
hello478 said:
(the total force, sum of resistive forces) with that velocity???
is this explanation fine?
Not sure what you mean by that. In the general case the truck is accelerating, so we have ##F_{net}=F_{static}+F_{resist}=ma##, ##F_{resist}## being negative. So the engine power would be ##F_{static}v=(ma-F_{resist})v##.
 
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  • #11
haruspex said:
Not sure what you mean by that.
i meant that we would multiply the force which causes to move the lorry with the velocity it creates
also is this applicable to all cases?
 
  • #12
hello478 said:
i meant that we would multiply the force which causes to move the lorry with the velocity it creates
You don't have to care what creates the velocity. What matters is that a force ##\vec F## is exerted at a point on a body while that point is moving with velocity ##\vec v##. The power transferred is ##\vec F\cdot\vec v##.
 
  • #13
I'm still worried about the signs:
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  • #14
F would be 8628.46+5200
 
  • #15
I agree
 
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