How Do Series Expansions Relate to Exponential Functions?

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e^(i Pi)+1=0
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limit as n→∞ of [itex]\frac{(2t)^n}{n!}[/itex] and [itex]\frac{(-t)^n}{n!}[/itex]

Answers are e2t-1 and e-t-1 but I don't know how to work them out, thanks.

edit: btw these are series
 
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If those are series you should fix up your question showing the limits of the series. Do you know ##e^a=\Sigma^\infty_0 \frac{a^n}{n!}##?
 
e^(i Pi)+1=0 said:
limit as n→∞ of [itex]\frac{(2t)^n}{n!}[/itex] and [itex]\frac{(-t)^n}{n!}[/itex]

Answers are e2t-1 and e-t-1 but I don't know how to work them out, thanks.

edit: btw these are series


Starting at n=1, it would seem? That would be unusual.
 
These are easy if you know that
[tex]\sum_{n=0}^\infty \frac{x^n}{n!}= e^x[/tex]