e^(i Pi)+1=0
- 246
- 1
limit as n→∞ of [itex]\frac{(2t)^n}{n!}[/itex] and [itex]\frac{(-t)^n}{n!}[/itex]
Answers are e2t-1 and e-t-1 but I don't know how to work them out, thanks.
edit: btw these are series
Answers are e2t-1 and e-t-1 but I don't know how to work them out, thanks.
edit: btw these are series