How Do You Analyze the Function f(x) = ax + (b/x) for Extrema and Concavity?

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SUMMARY

The discussion focuses on analyzing the function f(x) = ax + (b/x) for extrema and concavity, where a and b are positive constants. The first derivative, f'(x) = a - b/x², is used to identify critical points at x = ±√(b/a). The function is determined to be increasing on the intervals (-∞, -√(b/a)) and (√(b/a), ∞). The second derivative test is suggested for finding inflection points, confirming the need to analyze f''(x) for concavity.

PREREQUISITES
  • Understanding of calculus concepts, specifically derivatives and critical points.
  • Familiarity with the first and second derivative tests for extrema and concavity.
  • Knowledge of how to solve equations involving square roots.
  • Basic algebra skills for manipulating expressions and inequalities.
NEXT STEPS
  • Study the first derivative test in detail to confirm function behavior around critical points.
  • Learn about the second derivative test for determining concavity and inflection points.
  • Explore the implications of critical points on the graph of f(x) in terms of local maxima and minima.
  • Investigate the effects of varying constants a and b on the shape of the function f(x).
USEFUL FOR

Students studying calculus, particularly those focusing on optimization and graph analysis, as well as educators teaching these concepts in mathematics courses.

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Homework Statement



4) Let f(x)= ax+(b/x) where a and b are positive constants.
(a) Find in terms of a and b, the intervals on which f is increasing.
(b) Find the coordinates of all local maximum and minimum points.
(c) On what interval(s) is the graph concave up?
(d) Find any inflection points. Explain your answer.

The Attempt at a Solution



I need to take the derivative so it is f'(x)= a-b(x^-2) then I set this equal to zero to find the critical points, but then I'm not sure what value to solve for. X? If I do that I get critical points at +/- [tex]\sqrt{}b/a[/tex]
 
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If you set a- bx-1 equal to 0, the only thing left to solve for is x! Yes, [itex]x= \sqrt{b/a}[/itex] and [itex]x= -\sqrt{b/a}[/itex] are the critical values of x. What does that tell you about a, b, c, and d?
 
so is the function increasing from (-infinity,-root(b/a)) union (root(b/a),infinity)? Then should I take the second derivative set it equal to zero to find the inflection point
 

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