How Do You Calculate Acceleration at Different Points on a Helicopter Rotor?

AI Thread Summary
To calculate the acceleration at different points on a helicopter rotor, consider both the tip of the blade and a point moving towards the hinge. The flapping angle is defined as theta = A sin(omega*t), and the rotor's rotation speed is Omega. The acceleration experienced by a point, such as a worm moving inward, involves changes in both centripetal and tangential components due to varying radius and speed. As the worm moves closer to the hub, its tangential velocity and acceleration change accordingly. Utilizing polar coordinates can simplify the calculations for these accelerations.
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How would you calculate the acceleration of the following two points?

http://img341.imageshack.us/img341/917/helicoptor.jpg
Uploaded with ImageShack.us1) The tip of the helicopter blade

The diameter of the hub = d
The length of the rotor = l
The flapping angle: theta = A sin(omega*t)
The rotation speed of the rotor system = Omega2) A warm crawling from the tip to the hinge

The current position from the hinge = x
The speed along the blade = v (inward)

I'm trying to find the acceleration by the method of moving frame and it's getting tricky...
 
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In the picture shouldn't that be d/2 rather than 2/d as the radius from the centre to the hub edge?
Out of curiosity, what is A?

Nonetheless, in what direction would the worm feel an acceleration?
If the worm has moved to another position closer to the hub, how has the acceleration that it feels changed?
I think if you set up your equations regarding centripetal acceleration you should be able to solve.

As the worm moves inwards, the radius is changing (as above) so the worm's tangential velocity is also changing. Thus there is also a tangential acceleration, which you can solve for.

You could try using polar coordinates.
here is a description from Wiki
http://en.wikipedia.org/wiki/Circular_motion
 
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