How Do You Calculate Amplitude, Period, and Frequency in Simple Harmonic Motion?

[uha1]

A particle of mass 12 grams moves along the x axis. It has a restoring force F= -0.06 N/m. If it starts from x=10 cm with a speed of 20 cm/sec toward the equilibrium position, Find its amplitude, period, and frequency. Determine when the particle reaches the equilibrium point for the first time.


Edit:


I solved the question this way:

F= -w^2*m -> w=1/2(sqroot)

v=x*w
20=x*1/2(sqrt)
x=28.2

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T=2pi/w -> T=8.8

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a(accelaration) = -w^2*x
a= -14,1

Vf=Vi+a.t
t=1,141 sec.

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2nd way- and some one else solved the question with this way :

Let w = angular frequency, A = amplitude, T = time period
Acceleration = F / m = 0.06 / 0.012 = 5 m/s^2
Acc = w^2 * x
w^2 * 0.10 = 5
Simplifying, w = 5 (sqrt 2)
T = 2 pi / w
m * v^2 + m *w^2* x^2 = m* w^2 * A^2
0.04 + 0.5 = 50 * A ^2
A = (sqrt 1.08) / 10 m = sqrt 1.08 * 10 cm




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and I'M confused :(






Thanks,..

 

[Mentz114]

To get homework help you must show some effort. What have you done towards solving this ?

 

[uha1]

by the way thanks for reminding me Mentz, I'm new in the forum that's why.

 

[Mentz114]

Welcome to the forum. Assuming the particle will go into simple harmonic motion, we can use the force formula F = -kx to calculate k. The frequency is sqrt(k/m). Have a look here and you'll get some useful formulae -
http://hyperphysics.phy-astr.gsu.edu/hbase/shm.html#c1