How Do You Calculate Building Height Using Free Fall Formulas with Given Times?

AI Thread Summary
To calculate the height of a building using free fall formulas, the problem involves two phases: a 3.25-second acceleration and a 1.25-second deceleration. The relevant equation is Dy = V0t + 1/2at², where initial velocity (V0) is zero. By substituting the acceleration due to gravity (9.8 m/s²) and the total time of free fall (10.5625 seconds), the height is calculated to be approximately 51.8 meters. Clarification on the problem statement is needed for accurate assistance.
PhunPhysicsss
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Homework Statement


Figure out the height of the building using free fall formulas and only knowing two times: 3.25 second acceleration, 1.25 seconds decceleration. Find the height.

Homework Equations


Dy=V0t + 1/2at2 (only one I can think of that applies)

The Attempt at a Solution



Dy=V0t + 1/2at2
V0t=0

Dy= 1/2at2

Dy= .5(9.8m/s2)(10.5625)

Dy= 51.8 m

I am really stumped on this for some reason! I'm not even sure if I am using the correct formula. Any and all help is appreciated! Thanks y'all!
 
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Welcome to PF!

Hi PhunPhysicsss! Welcome to PF! :wink:
PhunPhysicsss said:
Figure out the height of the building using free fall formulas and only knowing two times: 3.25 second acceleration, 1.25 seconds decceleration. Find the height.

Sorry, I've no idea what you mean. :redface:

What's the full question? :smile:​
 
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