How do you calculate current in a changed parallel circuit?

[bobtheubs]

http://feat.putfile.com/profilepics/main/4/bobthebus-1313021205.jpg

Well this is my question, its not really homework or anything. I am just curious as to how you would do this. I was thinking that it would change at all. Since in a parallel circuit all the currents add up to the same number. So wouldn't you just divide 24 by 4, then minus 6 from the total I. Then times that by 3 and there you go. Thanks.

 

[cristo]

Could you write out the question please? I can't read that!

 

[BobG]

Your voltage didn't change, but your resistance changed, so the current has to change.

The picture is hard to read, but I take it all the resistances are equal and the circuit is broken at P?

If so, you now have a parallel circuit with three branches instead of four. If you work both equations using R and simplify, the difference between them should be pretty obvious.