How Do You Calculate Efficiency in a Carnot Cycle Involving Argon?

AI Thread Summary
To calculate efficiency in a Carnot cycle involving argon, the key parameters include the heat added (Qin) and the heat lost (Qout). The user has identified specific values for heat transfers and work done in the cycle, but is uncertain about how to define Qin and Qout for the efficiency formula. It is clarified that Qin should include the heat added during the relevant processes, while Qout represents the heat lost. The efficiency can be calculated using the formula η = 1 - Qout/Qin, but the user needs to determine the correct values for these variables based on the provided data. Understanding these definitions is crucial for accurately calculating the cycle's efficiency.
stonecoldgen
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Homework Statement


its part VI) of a big problem, where:

0.12 moles of argon (40) undergoes the cycle abca described in the graph. Process ab lies on a 540k isotherm.

In the previious 5 sub problems, i figured that:

Tc=270k
Qbc=670J (lost)
Qca=400J (added)
Wab=370J
Wabca=100J


The PV diagram has points a,b and c where:

a=(1.5X10-3, 3.6X105)
b=(3X10-3, 1.8X105)
c=(1.5X10-3, 1.8X105)







Homework Equations



Q=mc\DeltaT

\DeltaU=Q+W

\epsilon=1-Qout/Qin=1-Tlow/Thigh

The Attempt at a Solution


So it's basically using Qabca to find the efficiecy. The thing is that I am not sure what to use for the Qs.
 
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What is Qs supposed to represent? I don't see it in your problem statement.
 
RTW69 said:
What is Qs supposed to represent? I don't see it in your problem statement.

it's a plural for Q, I am not sure what to use for Qin and Qout
 
Remember this is NOT a carnot cycle. η= 1- Qout/Qin There is also a Qin between A and B. Do you know what it is? It is the Qout/ the Total Qin.
 
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