How Do You Calculate Electron Mobility in Copper?

Click For Summary
SUMMARY

The calculation of electron mobility in copper involves using the equation σ = neμe, where σ represents conductivity, ne is the density of free electrons, and μe is the electron mobility. The user, Staudy, is attempting to determine the density of free electrons based on the proportion of free electrons to copper atoms, which is one-to-one in copper. To accurately calculate electron mobility, it is essential to find the density of copper atoms, which can be sourced from material properties tables.

PREREQUISITES
  • Understanding of electrical conductivity and its relation to electron mobility
  • Familiarity with the properties of copper, including its atomic density
  • Knowledge of basic electrical equations and units
  • Ability to perform calculations involving ratios and densities
NEXT STEPS
  • Research the atomic density of copper to find the number of copper atoms per cubic centimeter
  • Learn how to calculate current density and its relationship to conductivity
  • Study the concept of electron mobility in metals and its significance in electrical engineering
  • Explore additional equations related to conductivity and electron behavior in conductive materials
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and materials scientists who are interested in understanding the electrical properties of metals, specifically copper, and how to calculate electron mobility accurately.

Staudinger
Messages
3
Reaction score
0
Hey all,

I have a pretty straightforward question about electron mobility in metals. We are given the length of a copper wire, it's radius, the current flowing through it, voltage drop across it, and the proportion of free electrons to copper atoms. I've found the current density, conductivity, resistance and resistivity of the wire, but I can't figure out how to calculate the electron mobility. We were given a few equations, one of which was specifically for metals,

\sigma = n_{e}\mu_{e}

in which
\sigma is conductivity
q is the charge of an electron
\mu_{e} is the the mobility of electrons
n_{e} is the density of free electrons

My problem is that I don't know how to translate the proportion of free electrons to copper atoms correctly. I tried using the ratio, which came out much too high, something like 10^24. We are not given the density of copper atoms in the wire, but I can find it in an appendix. Would it make sense to figure out how many copper electrons are in a cubic cm, and use that to find the density of free electrons?

Any help would be greatly appreciated, I feel as though I'm missing out on the aha! moment that would pull this all together.

Thanks!
Staudy
 
Physics news on Phys.org
There is one free electron to one copper atom, if that's what's stopping you.

Why don't you just write down your calculations. It can't be very long.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
8K
  • · Replies 1 ·
Replies
1
Views
206
Replies
19
Views
4K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
15K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 35 ·
2
Replies
35
Views
4K