How Do You Calculate Final Velocity with Given Force and Time?

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To calculate the final velocity of an object with an initial average velocity of -62 m/s, a mass of 0.462 kg, and an average force of 0.8 N applied over 5 seconds, the impulse-momentum theorem can be applied. The equation F = m(Vf - Vi)/t can be rearranged to find Vf, leading to a calculation of approximately -61.13 m/s. However, using the alternative equation Vf = Vi + at, where acceleration a is derived from a = F/m, yields a different result of -53.3 m/s. The discussion highlights confusion regarding the use of impulse and the correct application of equations to find final velocity. Ultimately, the initial calculation of -61.13 m/s is deemed correct by some participants in the discussion.
KatieLynn
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Homework Statement



Find the final velocity of the object if it is initially moving along the x-axis with average velocity of -62 m/s.

Other information
mass=.462kg
time=5s
average force = 0.8N
impulse=4

Homework Equations



F=m(Vf-Vi)/t

The Attempt at a Solution



I use the equation like this

(0.8N)=(.426kg)(Vf+62m/s)/(5s)

=-61.13m/s Is that right?
 
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I don't know why they gave you impulse, you can solve the problem with this equation:

Vf = Vi + at

where Vf=final velocity, Vi=initial velocity, a=acc. and t=time.

Remember - the acc. is .8/.462 because F=ma, so a=F/m.

Good luck!
 
Vf = Vi + atVf= (-62m.s) + (.8/.462)(5)

= -53.3 m/s

Thats what I got but it isn't right. I'm sure I didn't up the algebra, did I plug something in wrong?
 
well then i guess your initial approach is correct. the equation I gave might not work because i didnt read the part that said "avg velocity". I think your -61 is correct
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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