How Do You Calculate Maximum Acceleration of a Simple Harmonic Oscillator?

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To calculate the maximum acceleration of a simple harmonic oscillator with an amplitude of 0.49 m and a period of 3.7 seconds, the angular frequency (w) is determined using the formula w = 2π/T, resulting in w ≈ 1.698 rad/s. The maximum acceleration is then calculated using the equation a(max) = Aw^2, leading to a maximum acceleration of approximately 1.67 m/s². An initial attempt to find maximum velocity by dividing amplitude by time was incorrect; instead, using the correct formula for angular frequency is essential. The discussion highlights the importance of using the right equations in solving harmonic motion problems. Accurate calculations yield the correct maximum acceleration for the oscillator.
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Homework Statement


A simple harmonic oscillator has amplitude 0.49 m and period 3.7 sec.
What is the maximum acceleration?


Homework Equations


a(max)=Aw^2
w=angular frequency
Vmax=Aw
w= angular frequency


The Attempt at a Solution



I attempted to divide the Amplitude (.49m) by the time (3.7 sec) in order to find the maximum velocity. Plugging this value (.132432m/s) into the maximum velocity equation (Vmax=Aw) to solve for w I got a value of .27027027 which I plugged into the maximum acceleration equation to get a value of .035792549. Which was wrong
 
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w =2π/T
T:period.
i think you can find w with this equation.
 
That worked, thank you very much
 

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