How Do You Calculate Moles of Gas and CO2 Concentration Using the Ideal Gas Law?

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SUMMARY

The Ideal Gas Law is utilized to calculate the number of moles of gas at 1.00 atm in a 10.0 cm long cell with a cross-sectional area of 1.00 cm² at 298 K. Additionally, the concentration of CO₂ in a person's breath is determined using a 6.0 x 10² mL solution of 1.0 x 10⁻⁴ M NaOH with phenolphthalein indicator. The reaction CO₂ + OH⁻ yields HCO₃⁻ is critical for calculating the moles of CO₂ per liter of breath, based on the volume of breath required to change the indicator color.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of molarity and concentration calculations
  • Familiarity with acid-base reactions and indicators
  • Basic skills in unit conversions (mL to L)
NEXT STEPS
  • Learn how to apply the Ideal Gas Law in various scenarios
  • Study the calculation of molarity and concentration in solutions
  • Explore acid-base titration techniques and their applications
  • Investigate the properties and uses of phenolphthalein as an indicator
USEFUL FOR

Chemistry students, laboratory technicians, and professionals involved in gas analysis and titration methods will benefit from this discussion.

ANIMAL who
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#1-Use the Ideal Gas Law to calculate the number of moles of gas at 1.00atm in a cell 10.0cm long having a cross sectional area of 1.00cm^2 at 298K. (1ml=1cm^3)


#2-Lets say you start with 6.0 x 10^2 mL of 1.0 x 10^-4 M NaOH solution containing phenolphthalein indicator. The equation is CO_2 + OH^- yields HCO^-_3 (HCO bottom number of three with an overall negative charge) If 374 mL of a persons breath is required to turn the phenolphthalein from pink to colorless, calculate the number of moles of CO_2 per L of breath (ie., the concentration of CO_2) in this breath.
 
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ANIMAL who said:
#1-Use the Ideal Gas Law to calculate the number of moles of gas at 1.00atm in a cell 10.0cm long having a cross sectional area of 1.00cm^2 at 298K. (1ml=1cm^3)


#2-Lets say you start with 6.0 x 10^2 mL of 1.0 x 10^-4 M NaOH solution containing phenolphthalein indicator. The equation is CO_2 + OH^- yields HCO^-_3 (HCO bottom number of three with an overall negative charge) If 374 mL of a persons breath is required to turn the phenolphthalein from pink to colorless, calculate the number of moles of CO_2 per L of breath (ie., the concentration of CO_2) in this breath.

Show us what you have so far, Animal.
 

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