Engineering How Do You Calculate Power for Components C and E in a Circuit?

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To calculate power for components C and E in the circuit, the current ix is given as -3A, which affects the voltage across the Current Controlled Voltage Source (CCVS) E. The voltage V(E) is calculated as -6V based on ix, but for conservation of energy, E should be treated as 6V for calculations. Power can be calculated using the formula P=V*I, where the voltage across each element is known. The voltage across the rhombus is determined to be 6V, and it’s important to consider the signs for power calculations to indicate whether a component is a power source or sink. Understanding these relationships allows for accurate power calculations in the circuit.
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My biggest issue is I don't know what to do with the ix
So I really just need to know how to calculate power for C and E. Thank you!
 
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The ix current is given as 3A, but it is in the opposite direction, so we say ix = -3A.

E is a Current Controlled Voltage Source (CCVS) which has the voltage across it depending on the current ix. We know ix = -3A so V(E) = 2 * ix = -6V.

This doesn't make sense for the circuit though, as we need E = 6V for the law of conservation of energy not to be violated, so pretend E = 6V for your calculation.
 
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thank you!
 
jojobananas said:
My biggest issue is I don't know what to do with the ix

Actually, I think you could ignore it! * :rolleyes:

Simply because you know the current through each of the elements, and you know the magnitude of the voltage across each, so for each P=V.I

Okay, you may not have been told the voltage across that rhombus-thing :smile:
but the element in the centre has 10volts, and that on the right has 4volts, leaving (paying close attention to polarities) 6volts across the rhombus. (I must admit I didn't recognize it as a CCVS until Zryn pointed that out.)

It's not clear whether you need to attach a + or - sign to each power calculation, to indicate whether a power source or sink. If in doubt, it won't hurt to do so.

*you can do this in this case because there seems to have been more information provided on I's and V's than absolutely necessary
 

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