How Do You Calculate Proton Speed and Momentum in Special Relativity?

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Homework Help Overview

The discussion revolves around calculating the speed and momentum of a proton accelerated through a potential difference of 2000MV, within the context of special relativity. Participants are exploring the relevant equations and concepts related to relativistic kinetic energy and momentum.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the speed and momentum but is confused by varying results. Some participants suggest using the relativistic kinetic energy expression to determine velocity and momentum. Questions arise about the relationship between potential difference and kinetic energy, as well as how to convert units appropriately.

Discussion Status

Participants are actively discussing the problem, with some providing guidance on using the correct expressions for kinetic energy and momentum. There is recognition of the need to convert potential difference into joules, indicating a productive direction in the conversation. However, no consensus has been reached on a specific method or solution.

Contextual Notes

There is an emphasis on the urgency of the original poster's situation, as they are preparing for an exam. The discussion also highlights the importance of unit conversion in the calculations.

delongk
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Special Relativity I NEED HELP ASAP!

Find the speed and momentum of a proton (m=1.67*10^-27) that has been accelerated through a potential difference of 2000MV. Give your answers to three sig figs. Ans: .948c and 1.49*10^-18kg m/s

I keep trying different ways to get this, but keep getting different answers. How do you go about this problem? I need an answer ASAP because I leave in 15 minutes to take an exam.
 
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It's a bit late to be revising for an examination now, your best just trying to relax about it. However, this question is fairly straight forward. Do you know the expression for relativistic kinetic energy? Use this to find the velocity of the particle, then use the relativistic expression for momentum to find the moment of the proton.
 
delongk said:
Find the speed and momentum of a proton (m=1.67*10^-27) that has been accelerated through a potential difference of 2000MV. Give your answers to three sig figs. Ans: .948c and 1.49*10^-18kg m/s

I keep trying different ways to get this, but keep getting different answers. How do you go about this problem? I need an answer ASAP because I leave in 15 minutes to take an exam.
Use: [tex]KE = E - m_0c^2 = (\gamma -1)m_0c^2[/tex]

AM
 
Is 2000MV equal to the KE then?? How do you find KE to use that to find v? ANd I have studied for a week... I just couldn't get this one problem when I was reviewing this morning.
 
delongk said:
Is 2000MV equal to the KE then?? How do you find KE to use that to find v? ANd I have studied for a week... I just couldn't get this one problem when I was reviewing this morning.
Yes, the 2000mV is the KE. Use that to determine the [itex]\gamma[/itex]. That will allow you to determine v using:

[tex]\gamma = \frac{1}{\sqrt{1-v^2/c^2}}[/tex]

AM
 
Last edited:
delongk said:
Is 2000MV equal to the KE then?? How do you find KE to use that to find v? ANd I have studied for a week... I just couldn't get this one problem when I was reviewing this morning.
You must first convert the 2000MV into Joules, i.e. find the work done on the proton. Recall the voltage is defined as the work done per unit charge; thus, the energy supplied to the proton would be the product of the potential difference in volts and the charge of the proton in coulombs. Do you follow?
 
That's where I went wrong... I kept putting 2000MV into the KE and got the wrong answers... but I have to convert it to J. Thanks!
 
delongk said:
That's where I went wrong... I kept putting 2000MV into the KE and got the wrong answers... but I have to convert it to J. Thanks!
Yeah, that's right, an easy slip to make (I've done it myself a few times). Good luck with your exam. :smile:
 

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