How Do You Calculate Stress and Strain in a Stretched Copper Wire?

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SUMMARY

The discussion focuses on calculating stress and strain in a stretched copper wire with a diameter of 1.0mm and a length of 2.3m, using Young's modulus of 1.1 x 1011 Pa. Key calculations include determining the cross-sectional area (7.8 x 10-7 m2), strain (0.37), and the relationship between stress and strain using Young's modulus. The participants emphasize the need to derive stress from the known strain and Young's modulus, and subsequently calculate the force required to achieve that stress.

PREREQUISITES
  • Understanding of Young's modulus and its application in material science
  • Knowledge of basic physics equations related to stress and strain
  • Familiarity with geometric calculations for cross-sectional areas
  • Ability to manipulate units and perform dimensional analysis
NEXT STEPS
  • Study the relationship between stress, strain, and Young's modulus in detail
  • Learn how to calculate force from stress using the formula: Force = Stress × Area
  • Explore practical applications of stress and strain in engineering materials
  • Review examples of similar problems involving different materials and geometries
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Students in physics or engineering courses, particularly those studying material properties and mechanics, as well as educators looking for examples of stress and strain calculations in real-world applications.

DizzyDoo
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The last question on my homework (always the hardest).

Homework Statement


A wire of diameter 1.0mm and length 2.3m is made of copper. Young modulus is 1.1 x 10^11. Find:
a) The cross-section of the wire in m²
b) The strain if the wire is stretched by 0.85mm
c) The stress
d) The force necessary to cause the stress

Homework Equations


(Pie)r²
strain = extension/original length
stress = Force/area

The Attempt at a Solution


Here is my attempt, I get stuck at C, but please check what I've done so far.

A) if (pie)r² then stick that into the calculator, and I get 7.8 x 10 ^7
B) Extension/Original length= 0.85/2.3 = 0.37
c) Hmm, they ask for stress but there is no force given, so how do I work that out?
d) Now they ask the force needed to cause the stress, but I need that to work out the stress. Very confusing

Any help is greatly appreciated.
 
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DizzyDoo said:
The last question on my homework (always the hardest).

Homework Statement


A wire of diameter 1.0mm and length 2.3m is made of copper. Young modulus is 1.1 x 10^11. Find:
a) The cross-section of the wire in m²
b) The strain if the wire is stretched by 0.85mm
c) The stress
d) The force necessary to cause the stress

Homework Equations


(Pie)r²
strain = extension/original length
stress = Force/area

The Attempt at a Solution


Here is my attempt, I get stuck at C, but please check what I've done so far.

A) if (pie)r² then stick that into the calculator, and I get 7.8 x 10 ^7 you mean 7.8 x 10^-7 m^2[/color]
B) Extension/Original length= 0.85/2.3 = 0.37 Right equation, but again your units are lacking and decimal point is off[/color]
C) Hmm, they ask for stress but there is no force given, so how do I work that out? You have Young's modulus and you have calculated the strain...what is the formula that relates stess and strain?[/color]
d) Now they ask the force needed to cause the stress, but I need that to work out the stress. Very confusing once you have the stress, the force should be easy to calculate[/color]

Any help is greatly appreciated.
see above in red [/color].
 

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