How Do You Calculate the Angle in a Diffraction Grating Equation?

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ibysaiyan
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Diffracting grating?kinda confused?

Homework Statement


bits given:lamda(660nm) n=1,d=3.33, angle=?


Homework Equations


n(lambda)=dsin(theta)


The Attempt at a Solution



so from re-arranging the formula,etc i got this :6.66x^-7/3.33=sin(theta)
=>2x10^-7=sin(theta)
=>angle=1.14x10^-5(after inverse sin function) ? not sure if that's the answer =/
 
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With what you're given, the answer (in degrees) seems fine to me.

The Bob
 


k thanks a lot because some1 told me that i got my d wrong, =) which is not now
 


cant w8 to become astronomer =),need to work hard <.<,good stopped my gaming addiction.sorry if i wasnt allowed to type something out of context
 


As d was stated in the question, I can't see how it can be wrong. Good luck with your studies.

The Bob
 


Redbelly98 said:
What are the units for this value of d? 3.33 meters would be awfully large for a diffraction grating! :eek:

in the question was given that a diffraction grating is marked as 300lines/mm
a)find distance between slits (which i got 3.33 from 1/0.3)
 


lol yea distance between slits 3.33m lol can't be hmm
 


is probably mm
 


Redbelly98 said:
What are the units for this value of d? 3.33 meters would be awfully large for a diffraction grating! :eek:
I've been away from units for too long. Yer, Redbelly98 is right. If it is 3.33mm then the answer is wrong. I apologise for assuming it was a 'plug-in-the-values' question. What's your final answer?

The Bob
 


the answer i got is 3.33 for d .idk where i am messing things up.
 


Redbelly98 said:
That is the key here. In 1 mm, there are 300 lines. So each line must be ____?

hmm would it be: d=1/300000=3.33x10^-6