How Do You Calculate the Angular Speed of a Billiard Ball After a Strike?

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To calculate the angular speed of a billiard ball after a strike, consider the distance from the center of the ball to the point of impact, which is 10mm above the center. The ball's mass is 0.2kg, and its radius is 30mm, with a linear speed of 1m/s after the strike. The torque generated by the strike can be expressed as τ(t) = d * F(t), where d is the distance from the center to the point of impact. Using the relationship between linear momentum and angular momentum, the angular speed can be determined by applying the moment of inertia for a solid sphere. This approach allows for the calculation of angular speed despite the absence of specific force data.
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A billiard ball is cued by striking it horizontally at a distance d=10mm above the center of the ball. The ball has mass m=0.2kg and radius r=30mm. Immediately after the strike, the center-of-mass of the ball moves with linear speed v=1m/s. Find the angular speed of the ball immediately after the strike. Ignore friction between the ball and the table during the strike.

I need help solving this problem since i don't even know where to start. Even an initial pointer would help me loads.
Thanks in advance
 
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Realistically, the amount of English will depend on friction between cue and billiard, but since no useful information is given here, I think they want you to assume that the impact force is applied horizontally, which isn't a bad estimate, to be fair.

What you need to keep in mind is that while the impact force varies, the ratio of force applied to torque remains fixed at τ(t)=d*F(t). Now, you know that dp/dt = F(t) and dL/dt = τ(t) = d*F(t). So while you have no idea what the actual force profile F(t) is, you can still say that ΔL = d*ΔL. You know what Δp is from velocity and mass, so you can get ΔL. Knowing ΔL, you should be able to work out the angular momentum by looking up the moment of inertia for a solid sphere.
 
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