How Do You Calculate the Area of a Quadrilateral Using Vertices?

  • Thread starter Thread starter numb_dumb
  • Start date Start date
  • Tags Tags
    Area
numb_dumb
Messages
5
Reaction score
0
A(2,1) b(8,1) C(4,3) D(6,6)

let these be 4 points(vertices) of a quadrilateral

so i calculated it out as

2 1
8 1
4 3
6 6
2 1

multiplying diagonal elements
Area = |(2*1-8*1)+(8*3-1*4)+(4*6-3*6)+(6*1-2*6)/2|=7
but the answer is 14 and it gives different answers for different choice of co-ordinate order
so how to judge which one is correct?
any limitation to use this rule?
my heads going crazy over this...
 
Mathematics news on Phys.org
You're trying to use the fact that the area of a convex quadrilateral is the absolute value of half the cross-product of the diagonals? It's easier to compute the diagonals first, and make sure that the lengths you compute are really those of the diagonals

If you draw a lines between adjacent points in the order you've given you don't get a convex polygon.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top